An object weighs 60.0N in air, 48.2N in a certain liquid ...
An object weighs 60.0N in air, 48.2N in a certain liquid X, and 44.9N in water, Calculate the relative density of X
3.300
1.279
0.932
0.782
Correct answer is D
R.d = Wt in Air-Wt in Air-Wt in water
= 60.0−48.260.0−44.9
= 0.782
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