1x−1−1x+2
1x+1+1x−2
1x+1−1x−2
1x−2+1x+2
Correct answer is A
3x2+x−2 = 3(x−1)(x+2)
Ax−1 + Bx+2
A(x + 2) + B(x - 1) = 3
when x = 1, 3A = 3 → a = 1
when x = -2, -3B = 3 → B = -1
= 1x−1−1x+2
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