49.2oC
60.6oC
80.0oC
84.7oC
Correct answer is A
85\(\Omega\) ........100oC
52\(\Omega\) ........\(\theta\)oC
20\(\Omega\) ........0oC
\(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}\)
\(\theta = \frac{32 \times 100}{65} = 49.2^oC\)
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