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An electromagnetic wave of frequency 5.0 x 1014Hz...

An electromagnetic wave of frequency 5.0 x 1014Hz, is incident on the surface of water of refractive index 43. Taking the speed of the wave in air as 3.0 x 108ms-1, calculate the wavelength of the wave in water.

A.

2.2 x 10-6m

B.

1.7 x 10-7m

C.

8.0 x 10-7m

D.

6.0 x 10-7m

E.

4.5 x 10-7m

Correct answer is E

anw=λaλw

43=λaλ

λw=vf

= 3.0×1085.0×1014=0.6×106

λw=34λa=34×0.6×106

= 4.5 x 10-7m