Two capacitors C1 and C2 are connec...
Two capacitors C1 and C2 are connected as shown in the diagram. The capacitance C2 is twice C1. When the key is opened, the energy stored up in C1 is W. If the key is later closed and the system is allowed to attain electrical equilibrium, the total energy stored in the system will be
\(\frac{1}{2}\)W
\(\frac{2}{3}\)W
W
2w
3W
Correct answer is E
E = \(\frac{1}{2} Cr^2 = \frac{1}{2}(C-1 + C_2)V^2 = (3C_1)V^2\)
= 3(\(\frac{1}{2}C_1v^2\)) = 3W
Similar Questions
The maximum and minimum thermometer reads the ...
The instantaneous value of the induced e.m.f as a function of time is ε = εo sin ωt where εo is ...
A piece of wire gauze can be made to lie on water because ...
Which of the following is correct about light and sound waves? ...