A body moving with uniform acceleration has two points(5, 15) and (20, 60) on the velocity-times graph of its motion. Calculate the acceleration
0.25ms-2
3.00ms-2
4.00ms-2
9.00ms-2
16.00ms-2
Correct answer is B
slope = acceleration
a = \(\frac{v_2 - v_1}{t_2 - t_1} = \frac{60- 15}{20 - 5}\)
= 3ms-2