A ball is projected horizontally from the top of a hill with a velocity of 20m^-1. If it reaches the ground 4 seconds later, what is the height of the hill? (g = 10ms^-2)

20m

40m

80m

160m

200m

Correct answer is C

Initial horizontal velocity = 20ms^-1

Initial vertical velocity = 0

s = ut + \(\frac{1}{2}gt^2\) = 0 x 5 x 4²

= 80m

See all Physics questions & answers

See more JAMB questions & answers

A ball is projected horizontally from the top of a hill with a velocity of 20m-1. If it reaches the ground 4 seconds later, what is the height of the hill? (g = 10ms-2)