A 500kg car which was initially at rest travelled with an acceleration of 5m sec-2, its kinetic energy after 4 seconds was

A.

105J

B.

2.5 x 103J

C.

2 x 103J

D.

5 x 103J

E.

5 x 105J`

View answer & explanation

Correct answer is A

K.E = \(\frac{1}{2}\)mv2; m (at + u)2

since, v = at + u = \(\frac{1}{2}\) x 500 [(5 x 4)+ 0]2

= 105J

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