A cell has an open circuit voltage V₁ and a closed circuit voltage V₂ when a current is flowing through it. Therefore, the internal resistance of the cell is

\(\frac{V_2}{I}\)

\(\frac{V_1}{I}\)

\(\frac{(V_1 + V_2)}{I}\)

\(\frac{(V_1 - V_2)}{I}\)

\(\frac{(V_2 - V_1)}{I}\)

Correct answer is E

On open circuit, V₁ = I; On closed circuit V₂ = IR + Ir

V₂ = V₁ + Ir

r = \(\frac{(V_2 - V_1)}{I}\)

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A cell has an open circuit voltage V1 and a closed circuit voltage V2 when a current is flowing through it. Therefore, the internal resistance of the cell is