\(\frac{V_2}{I}\)
\(\frac{V_1}{I}\)
\(\frac{(V_1 + V_2)}{I}\)
\(\frac{(V_1 - V_2)}{I}\)
\(\frac{(V_2 - V_1)}{I}\)
Correct answer is E
On open circuit, V1 = I; On closed circuit V2 = IR + Ir
V2 = V1 + Ir
r = \(\frac{(V_2 - V_1)}{I}\)
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