A calorimeter of thermal capacity 80j contains 20g of wat...
A calorimeter of thermal capacity 80j contains 20g of water at 25°C. Water at 100°C is added so that the final temperature of the set-ups is 50°C. The amount of water added is (Heat capacity of water = 4.18J/g/°C)
20g
25g
45g
50g
100g
Correct answer is A
Heat lost = heat gained
mcθ = cθ + mcθ
m x 4.18 x (100 - 50) = 80(50 -25) + [20 x 4.18] x (50 - 25)
m = 20g
A simple pendulum with a period of 2.0s has its length doubled. Its new period is ...
Which of the following types of thermometer is used for the calibration of other thermometers? ...
The period of a wave is 0.02 second. Calculate its wavelength if its speed is 330 ms-1...
One watt-hour is equivalent to ...
A metal rod has a length of 100cm at 200°C. At what temperature will its length be 99.4cm. If th...