What is the relative permitivity of a capacitor if its capacitance with a medium as dielectric is 16 farads and its capacitance with vacuum as dielectric is 2 farads?

A.

0

B.

\(\frac{1}{2}\)

C.

2

D.

8

E.

32

View answer & explanation

Correct answer is D

E = Er x E0

16 = Er x 2

Er = 8

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