A sector of a circle of radius 14cm containing an angle 60o is folded to form a cone. Calculate the radius of the base of the cone.

A.

\(5\frac{1}{2}cm\)

B.

\(4\frac{2}{3}cm\)

C.

\(3\frac{1}{2}cm\)

D.

\(2\frac{1}{3}cm\)

Correct answer is D

\(r=\frac{\theta \times l}{360^{\circ }}\\
r=?, \theta =60^{\circ }\), l = radius of the orginal sector of a circle = 14cm
\(r=\frac{60\times 14}{360}=\frac{7}{3}=2\frac{1}{3}cm\)