\(\frac{2-x}{12xyz}\)
\(\frac{2z-3x}{12xyz}\)
\(\frac{4z-3x}{12xyz}\)
\(\frac{8z-9x}{12xyz}\)
Correct answer is D
\(\frac{2}{3xy} - \frac{3}{4yz} = \frac{2(4)-3(3x)}{12xyz} = \frac{8z-9x}{12xyz}\)
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