In the diagram, PQRW is a circle. Line P, V and QR are produced to meet at M, where ∠WMR = 30o and |WM| = |MR| Find the value of x
10o
25o
35o
60o
Correct answer is B
MPQ = PQM = 3x; ∆MPQ
MPQ + PQM + PMQ = 180° 3x + 3x + 30° = 180°
\(6x \times 30° = 180° 6x + 180° - 30°; 6x + 150°\)
\(x = \frac{150}{6} = 25^{\circ}\)