A particle moves in a circular orbit of radius 0.02m. If the speed of the particle is 0.88ms-1, calculate its frequency in cycles per second

A.

2.0Hz

B.

7.0Hz

C.

8.8Hz

D.

14.0Hz

E.

17.6Hz

View answer & explanation

Correct answer is B

W = \(\frac{v}{r}\)

= \(\frac{0.88}{0.02}\) = 44 rad/s

2\(\pi\)F = W = 44

F = \(\frac{44}{2 \times 3.142}\)

= 7Hz

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