A plane inclined at an angle of 30^o to the horizontal has an efficiency of 60%. The force parallel to the plane required to push a load of 120N uniformly up the plane is

60N

100N

120N

200N

240N

Correct answer is B

V.R = \(\frac{1}{sin 30}\) = 2

Efficiency = \(\frac{m.A}{V.R}\) x 100%

60 = \(\frac{120}{effort}\) x \(\frac{1}{2}\) x 100

Effort = 100N

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A plane inclined at an angle of 30o to the horizontal has an efficiency of 60%. The force parallel to the plane required to push a load of 120N uniformly up the plane is