The lower and upper fixed points marked on a mecury-in-glass thermometer are 210mm apart. The end of the mercury column in the tube is 49mm above the lower fixed point in a room. What is the temperature of the room in degrees Celsius?

A.

55.3oC

B.

23.3oC

C.

49.0oC

D.

16.1oC

E.

76.7oC

Correct answer is B

210mm .... 100oC

49mm .... \(\theta\)

0mm .... 0oC

\(\frac{49 - 0}{210 - 0}\) = \(\frac{\theta - 0}{100 - 0}\)

\(\frac{49}{210}\) = \(\frac{\theta}{100}\)

\(\theta\) = 23.3oC