0.4N
100.0N
250.0N
1000.0N
Correct answer is B
F = ma and V2 = U2 + 2aX
F = m\(\frac{(V^2 - U^2)}{2X}\)
= 0.04\(\frac{(500^2 - 0^2)}{2 \times 50}\)
F = 100N
The potential energy in an elastic string of force constant k, which has an extension X is? ...
The relationship between the period T and the length l of a simple pendulum is T = 2\( \pi...
A force of 500N1 is applied to a steel wire of cross-sectional area 0.2m2, The tensile stress is...