The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 150Hz?
1
2
3
4
Correct answer is B
The fundamental frequency (Fo) = 40Hz
First overtone f1 = 2 \(\times\) 40 = 80
Second overtone f2 = 3 \(\times\) 40 = 120
Third overtone f3 = 4 \(\times\) 40 = 160.
Hence there are just two overtones between 40Hz and 150Hz