Two strings of the same length and under the same tension...
Two strings of the same length and under the same tension gives notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding ratio of
2 : 1
1 : 2
1 : 4
1 : 16
Correct answer is D
F = 12L√Tm
F1F2 = √m2m1
14 = √m2m1
m2m1 = 116
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