A tap supplies water at 25^oC while another supplies water at 75^oC. If a man wishes to bathe with water at 40^oC, the ratio of the mass of cold water to the mass of hot water required is

1 : 3

15 : 8

7 : 3

3 : 1

Correct answer is C

Heat lost = heat gained

m_h x c x (75 - 40) = m_c x c x (40 - 25)

\(\frac{m_h}{m_c}\) = \(\frac{35}{15}\)

= \(\frac{7}{3}\)

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A tap supplies water at 25oC while another supplies water at 75oC. If a man wishes to bathe with water at 40oC, the ratio of the mass of cold water to the mass of hot water required is