A lamp is rated 240V, 60W. The resistance of the filament is
960\(\Omega\)
16\(\Omega\)
15\(\Omega\)
4\(\Omega\)
Correct answer is A
P = \(\frac{V_2}{R}\) \(\Rightarrow\) R = \(\frac{V_2}{p}\) = \(\frac{240\times 240}{60}\) = 960\(\Omega\)
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