A sonometer wire of length 100cm under a tension of 10N, has a frequency of 250Hz. Keeping the length of the wire constant, the tension is adjusted to produce a new frequency of 350Hz. The new tension is

A.

5.1N

B.

7.1N

C.

14.0N

D.

19.6N

View answer & explanation

Correct answer is D

\(\frac{F_1}{F_2}\) = \(\sqrt\frac{T_1}{T_2}\)

\(\frac{250}{350}\) = \(\sqrt\frac{10}{T_2}\)

T2 = 19.6N

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