A car moving with a speed of 90kmh-1 was brought uniforml...
A car moving with a speed of 90kmh-1 was brought uniformly to rest by the application of the brakes in 10s. How far did the car travel after the brakes were applied?
125m
150m
250m
15km
Correct answer is A
speed = \(\frac{90 \times 10^3}{3600}\) = 25ms-1
Acceleration = velocity change / time = 25 / 10
: Acceleration = 2.5
Using S = Ut + \(\frac{1}{2}\) at^2
S = \(\frac{1}{2}\) X 2.5 X 10^2 = 125m
The compressed regions and the space-out regions in longitude wave are refers to as ...
When vibration occurs in air column, the distance between a node and an antinode is equal to ...
A gas occupies a certain volume at 27°C. At what temperature will its volume be twice times...
Notes of the same frequency sounded on a guitar and trumpet may differ in I. loudness II. Pitch ...