The angle of depression of a point Q from a vertical towe...
The angle of depression of a point Q from a vertical tower PR, 30m high, is 40°. If the foot P of the tower is on the same horizontal level as Q, find, correct to 2 decimal places, |PQ|.
35.75m
25.00m
22.98m
19.28
Correct answer is A
\(\tan 40° = \frac{30}{|PQ|}\)
\(|PQ| = \frac{30}{\tan 40°} = \frac{30}{0.839}\)
= 35.75m
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