The maximum permissible current through a galvanometer G of internal resistance 10\(\Omega\) is 0.05A. A resistance R is used to convert G into a voltmeter with a maximum reading of 100V. Find the value of R and how it is connected to G

A.

20,000 ohms in parallel

B.

19,990 ohms in series

C.

1990 ohms in series

D.

100 ohms in series

Correct answer is C

No explanation has been provided for this answer.