A 40-W instrument has a resistance of 90\(\Omega\). On what voltage should it be operated normally?

A.

60V

B.

150V

C.

225V

D.

3600V

View answer & explanation

Correct answer is A

P = \(\frac{V}{R}\)

V = \(\sqrt{PR}\)

V = \(\sqrt{40 \times 90}\)

= 60V

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