The external and internal diameter of a tube are measured as (32 ± 2)mm and (21 ± 1)mm respectively. Determine the percentage error in the thickness of the tube.

A.

27%

B.

14%

C.

9%

D.

3%

View answer & explanation

Correct answer is C

Actual thickness = 34 - 22 = 12

error thickness = 30 - 20 = 10

error = 12 - 10 = 2mm that is, (11 ± 1)mm

%error = \(\frac{1}{11}\) x \(\frac{100}{1}\)

= 9%

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