A 5kg block is released from rest on a smooth plane inclined at an angle of 30o to the horizontal. What is the acceleration down the plane? [g = 10ms-2]

A.

5.0 ms-2

B.

5.8 ms-2

C.

8.7 ms-2

D.

25.0 ms-2

View answer & explanation

Correct answer is A

ma = mgsin\(\theta\)

a = \(\frac{5 {\times} 10 {\times} sin30}{t}\)

a = 5ms2

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