The displacement d produced in a glass block of thickness...
The displacement d produced in a glass block of thickness t and refractive index n when an object is viewed through it is
t – n
t (1 + 1/n)
t (1-1/n)
t (1/n - 1)
Correct answer is C
n = \(\frac {\text{real depth}}{\text {apparent depth}{}}\)
n = \(\frac {t}{t-d}\)
\(\frac{t - d}{1}\) = \(\frac{t}{n}\)
-d = \(\frac{t}{n}\) - t
d = - \(\frac{t}{n}\) + t
d = t - \(\frac{t}{n}\)
d =t (1 - \(\frac{1}{n}\))
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