How many grams of water at 17^oC must be added to 42g of ice at 0^oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 10⁵Jkg^-1, specific heat capacity of water = 4200Jkg^-1k^-1]

200g

300g

320g

400g

Correct answer is A

Heat lost = Heat gained

mc\(\theta\) = mL

m x 4200 x 17 = 42 x 3.4 x 10⁵

therefore, m = 200g

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How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 105Jkg-1, specific heat capacity of water = 4200Jkg-1k-1]