A uniform meter rule weighing 0.5N is to be pivoted on a knife-edge at the 30cm-mark. where will a force of 2N be placed from the pivot to balance the meter rule?
95cm
25cm
20cm
5cm
Correct answer is D
Taking moment about P,
2 x d = 0.5 x (50 - 30)
2x = 10
x = 5 cm