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In the diagram above, O is the center of the circle of ra...

In the diagram above, O is the center of the circle of radius 3.5cm, ∠POQ = 60°. What is the area of the minor sector POQ?

[Take π = 22/7].

In the diagram above, O is the center of the circle of radius 3.5cm, ∠POQ = 60°. What is the area of the minor sector POQ?

[Take π = 22/7].

A.

1481/2cm2

B.

77cm2

C.

321/12cm2

D.

65/12cm2

E.

15/6cm2

Correct answer is D

Area of sector = \frac{\theta}{360°} \times \pi r^2

= \frac{60}{360} \times \frac{22}{7} \times 3.5 \times 3.5

= \frac{77}{12}

= 6\frac{5}{12} cm^2