![In the diagram above, O is the center of the circle of radius 3.5cm, ∠POQ = 60°. What is the area of the minor sector POQ?
[Take π = 22/7].](/img/aptitude-tests/questions/10313.jpg "In the diagram above, O is the center of the circle of radius 3.5cm, ∠POQ = 60°. What is the area of the minor sector POQ?
[Take π = 22/7].")
In the diagram above, O is the center of the circle of radius 3.5cm, ∠POQ = 60°. What is the area of the minor sector POQ?
[Take π = 22/7].
A.
1481/2cm2
B.
77cm2
C.
321/12cm2
D.
65/12cm2
E.
15/6cm2
Correct answer is D
Area of sector = \(\frac{\theta}{360°} \times \pi r^2\)
= \(\frac{60}{360} \times \frac{22}{7} \times 3.5 \times 3.5\)
= \(\frac{77}{12}\)
= \(6\frac{5}{12}\) cm\(^2\)