If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
\(\frac{p_{0}} {5}\)
\(\frac{4p_{0}}{5}\)
p\(_{0}\)
5P\(_{0}\)
Correct answer is D
p\(_{1}\) = P\(_{0}\), V\(_{1}\) = V\(_{0}\), V\(_{2}\) = \(\frac{1}{5}\)V\(_{0}\) P\(_{2}\) = ?
P\(_{1}\)V\(_{1}\) = P\(_{2}\)V\(_{2}\)
P\(_{2}\) = \(\frac{P_{1}V_{1}}{V_{1}}\)
= \(\frac{\not P_{o}V_{o}}{\frac{1}{5}P_{o}}\) = 5\(\not P_{o}\)
When the temperature of a liquid increases, its surface tension
decreases
increases
remains constant
increases then decreases
Correct answer is A
Surface tension decreases by:
* Increasing liquid's temperature
* Adding soap to the liquid
\(\frac{5}{3}\)
\(\frac{4}{3}\)
\(\frac{3}{4}\)
\(\frac{7}{10}\)
Correct answer is C
R.D = \(\frac{\text {weigh in air - weigh in liquid X}}{\text {weigh in air - weigh in water}}\)
= \(\frac{10 - 7}{10 - 6} = \frac{3}{4}\)
5.0 x 10\(^{-4}\)Nm\(^{-2}\)
5.0 x 10\(^{-5}\)Nm\(^{-2}\)
2.0 x 10\(^{-8}\)Nm\(^{-2}\)
2.0 x 10\(^{9}\)Nm\(^{-2}\)
Correct answer is D
Young's modulus \(\frac{stress}{strain}\)
Strain = \(\frac{e}{l} = \frac{0.05}{10} = \frac{10^{7}}{0.005}\)
2 x 10\(^{9}\)Nm\(^{-2}\)
When the breaks in a car are applied, the frictional force on the tyres is?
a disadvantage because it is in the direction of the motion of the car
a disadvantage because it is in the opposite direction of the motion of the car
an advantage because it is in the direction of the motion of the car
an advantage because it is in the opposite direction of the motion of the car
Correct answer is D
Frictional force opposes motion