If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
\( 2.93 \times 10^{15}\)Hz
\( 3.59 \times 10^{16}\)Hz
\( 5.39 \times 10^{15}\)Hz
\( 1.24 \times 10^{15}\)Hz
Correct answer is D
h = \( 6.6 \times 10^{-34}\)Js, 1eV = \( 1.6 \times 10^{-19}\)J, \(E_1\) = - 8.6eV, \(E_2\) = - 3.5eV, f = ?
ΔE = hf
f = \(\frac{ΔE}{h}\)
ΔE = \(E_2\) - \(E_1\) = - 3.5eV - (- 8.6eV) = 5.1eV
but 5.1eV = 5.1 X \( 1.6 \times 10^{-19}\) = \( 8.16 \times 10^{-19}\)J
f = \(\frac{8.16 \times 10^{-19}}{ 6.6 \times 10^{-34}}\)
Therefore, f = \( 1.24 \times 10^{15}\)Hz
longer than \(10^{-6} m\).
shorter than \(10^{-6} m\).
shorter than \(10^{3} m\).
longer than \(10^{3} m\).
Correct answer is A
The range of wavelengths for infrared waves is given as \(10^{-3}\) m to \(10^{-6}\)m. This means that the wavelength of the radiation is longer than \(10^{-6} m\) but shorter than \{10^{-3} m\). Therefore, the only correct option is that the wavelength is longer than \(10^{-6} m\).
\(30^0\)
\(60^0\)
\(45^0\)
\(0^0\)
Correct answer is C
Maximum Range R = \(\frac{u^2sin2\theta}{g}\)
maximum height H = \(\frac{u^2sin^2\theta}{2g}\)
But R : H = 4
\(\frac{u^2sin2\theta}{g}\) : \(\frac{u^2sin^2\theta}{2g}\) = 4
\(\frac{u^2sin2\theta}{g} \times\frac{2g}{u^2sin^2\theta}\) = 4
\(\frac{2sin2\theta}{sin^2\theta}\) = 4
since 2sinΘ = 2sinΘcosΘ
\(\frac{2 \times 2sin\theta cos\theta}{sin^2\theta}\) = 4
\(\frac{4sin\theta cos\theta}{sin^2\theta}\) = 4
\(\frac{sin\theta cos\theta}{sin^2\theta}\) = 1
\(\frac{cos\theta}{sin\theta}\) = 1
\(\frac{sin\theta}{cos\theta}\) = 1
\(tan \theta\) = 1
\(\theta = tan^{-1}1\) = 45°
A charge of 10 C is transferred across a potential difference of 220 V. Determine the work done.
22J
2200J
210J
230J
Correct answer is B
The work done in moving a charge across a potential difference is given by the formula W = QV, where W is the work done, Q is the charge and V is the potential difference. Substituting the given values, we get W = 10 C * 220 V = 2200 J. Hence, the work done is 2200 J.
1.550m
0.646m
5.120m
0.195m
Correct answer is B
f = 512Hz, V = 331m/s λ = ?
V = f λ
λ = \(\frac{v}{f} = \frac{331}{512}\)
λ = 0.646m.
Sales Marketer at Shulifang Biotechnology FZE
Chief Information Security Officer at Standard Chartered Bank
Research Officer at TEDxMaitama Official
Knowledge Management and Learning Senior Advisor at WaterAid
Environment Health and Safety (EHS) Operations Manager at British American Tobacco
Solar Installer at VGL Energy and Power Technology
Sales Representative at VGL Energy and Power Technology
Administrative Assistant at VGL Energy and Power Technology
Sanitation and Hygiene Coordinator at WaterAid Nigeria