Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

166.

A hunter fires a gun at a point 408 m away from a cliff. If he hears an echo 2.4 s later, determine the speed of the sound wave

A.

340 ms\(^{-1}\)

B.

380 m s\(^{-1}\)

C.

400 m s \(^{-1}\)

D.

680 m s\(^{-1}\)

Correct answer is A

speed of the sound wave = \(\frac{distance * 2}{time}\)

= \(\frac{408 * 2}{2.4}\)

: speed of the sound wave = 340 ms\(^{-1}\)

167.

When the direction of vibration of the particles of a medium is perpendicular to the direction of propagation of a wave, the wave is said to be--------

A.

longitudinal

B.

transverse

C.

mechanical

D.

a sound wave

Correct answer is B

In physics, a transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance.

This is in contrast to a longitudinal wave which travels in the direction of its oscillations. Water waves are an example of transverse wave.

169.

Gamma rays are produced when?

A.

high velocity electrons are abruptly stopped in metals

B.

energy changes occur within the nuclei of atoms

C.

energy changes occur within the electronic structure of atoms

D.

electrons are deflected in very strong magnetic fields

Correct answer is B

Gamma rays are produced in the disintegration of radioactive atomic nuclei and in the decay of certain subatomic particles.

Gamma radiation is emitted by excited nuclei or other processes involving subatomic particles;

it often accompanies alpha or beta radiation, as a nucleus emitting those particles may be left in an excited (higher-energy) state.

170.

If the kinetic energy of an electron is 100 eV, what is the wavelength of the de-Broglie wave associated with it? [h = 6.6 x 10\(^{-34}\) J s, e = 1.6 x 10\(^{19}\)C, m\(_{e}\), = 9.1 x 10\(^{-31}\) kg]

A.

1.22 x 10\(^{-10}\)m

B.

4.10 x 10\(^{-10}\)m

C.

3.90 x 10\(^{-10}\)m

D.

5.50 x 10\(^{-14}\)m

Correct answer is D

de broglie wavelength formula in terms of kinetic energy:

 λ = \(\frac{h}{\sqrt{2mE}}\) 

 λ = \(\frac{6.6 *10^{-34}}{\sqrt{2 *9.1*10^{-31} *100 }}\)

 λ = 5.50 x 10\(^{-14}\)m