Data Interpretation questions test one's ability in analysing data, inspecting the elements in data and interpreting them to extract maximum information from the given set of data or information. The data is usually given in the form of charts, tables and graphs.
Practise with our Data Interpretation questions and answers to help you know what to expect, improve your speed and confidence and be really prepared for the actual test.
Study the following table and answer the questions.
Classification of 100 Students Based on the Marks Obtained by them in Physics and Chemistry in an Examination.
27
32
34
41
Correct answer is B
We have 60% of 50 = ( 60/100 x 50 ) = 30
Therefore Required number
= No. of students scoring 30 and above marks in Physics
= 32
Study the following table and answer the questions.
Classification of 100 Students Based on the Marks Obtained by them in Physics and Chemistry in an Examination.
3
4
5
6
Correct answer is D
Required difference
= (No. of students scoring 30 and above marks in Chemistry)
- (Number of students scoring 30 and above marks in aggregate)
= 27 - 21
= 6
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
What is the overall percentage of Tarun?
52.5%
55%
60%
63%
Correct answer is C
Aggregate marks obtained by Tarun
= [ (65% of 150) + (35% of 130) + (50% of 120)
+ ((77% of 100) + (80% of 60) + (80% of 40) ]
= [ 97.5 + 45.5 + 60 + 77 + 48 + 32 ]
= 360.
The maximum marks (of all the six subjects)
= (150 + 130 + 120 + 100 + 60 + 40)
= 600.
Therefore Overall percentage of Tarun = ( 360/600 x 100 ) % = 60%.
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
In which subject is the overall percentage the best?
Maths
Chemistry
Physics
History
Correct answer is A
We shall find the overall percentage (for all the seven students) with respect to each subject.
The overall percentage for any subject is equal to the average of percentages obtained by all the seven students since the maximum marks for any subject is the same for all the students.
Therefore, overall percentage for:
(i) Maths = [ 1/7 x (90 + 100 + 90 + 80 + 80 + 70 + 65) ] % = [ 1/7 x (575) ] % = 82.14%.
(ii) Chemistry = [ 1/7 x (50 + 80 + 60 + 65 + 65 + 75 + 35) ] % = [ 1/7 x (430) ] % = 61.43%.
(iii) Physics = [ 1/7 x (90 + 80 + 70 + 80 + 85 + 65 + 50) ] % = [ 1/7 x (520) ] % = 74.29%.
(iv) Geography = [ 1/7 x (60 + 40 + 70 + 80 + 95 + 85 + 77) ] % = [ 1/7 x (507) ] % = 72.43%.
(v) History = [ 1/7 x (70 + 80 + 90 + 60 + 50 + 40 + 80) ] % = [ 1/7 x (470) ] % = 67.14%.
(vi) Comp. Science = [ 1/7 x (80 + 70 + 70 + 60 + 90 + 60 + 80) ] % = [ 1/7 x (510) ] % = 72.86%.
Clearly, this percentage is highest for Maths.
The following table gives the percentage of marks obtained by seven students in six different subjects in an examination.
The Numbers in the Brackets give the Maximum Marks in Each Subject.
What was the aggregate of marks obtained by Sajal in all the six subjects?
409
419
429
449
Correct answer is D
Aggregate marks obtained by Sajal
= [ (90% of 150) + (60% of 130) + (70% of 120)
+ (70% of 100) + (90% of 60) + (70% of 40) ]
= [ 135 + 78 + 84 + 70 + 54 + 28 ]
= 449