Data Interpretation questions test one's ability in analysing data, inspecting the elements in data and interpreting them to extract maximum information from the given set of data or information. The data is usually given in the form of charts, tables and graphs.
Practise with our Data Interpretation questions and answers to help you know what to expect, improve your speed and confidence and be really prepared for the actual test.
The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year since the foundation of the Company in 1995.
128
112
96
88
Correct answer is D
Required difference
= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)
= 88
A school has four sections A, B, C, D of Class IX students.
The results of half yearly and annual examinations are shown in the table given below.
Which section has the minimum failure rate in half yearly examination?
Section A
Section B
Section C
Section D
Correct answer is D
Total number of failures in half-yearly exams in a section
= [ (Number of students who failed in both exams) + (Number of students who failed in half-yearly but passed in Annual exams) ] in that section
Therefore Failure rate in half-yearly exams in Section A
= [ Number of students of Section A who failed in half-yearly/Total number of students in Section A x 100 ] %
= [ (28 + 14)/(28 + 14 + 6 + 64) x 100 ] % = [ 42/112 x 100 ] % = 37.5%
Similarly, failure rate in half-yearly exams in:
Section B [ (23 + 12)/(23 + 12 + 17 + 55) x 100 ] % = [ 35/107 x 100 ] % = 32.71%
Section C [ (17 + 8)/(17 + 8 + 9 + 46) x 100 ] % = [ 25/80 x 100 ] % = 31.25%
Section D [ (27 + 13)/(27 + 13 + 15 + 76) x 100 ] % = [ 40/131 x 100 ] % = 30.53%
Clearly, the failure rate is minimum for Section D.
A school has four sections A, B, C, D of Class IX students.
The results of half yearly and annual examinations are shown in the table given below.
Which section has the maximum success rate in annual examination?
Section A
Section B
Section C
Section D
Correct answer is A
Total number of students who passed in annual exams in a section
= [ (No. of students who failed in half-yearly but passed in annual exams) + (No. of students who passed in both exams) ] in that section
Therefore Success rate in annual exams in Section A
= [ No. of students of Section A who passed in annual exams/Total number of students in Section A x 100 ] %
= [ (14 + 64)/(28 + 14 + 6 + 64) x 100 ] %
= [ 78/112 x 100 ] %
= 69.64%.
Similarly, success rate in annual exams in:
Section B [ (12 + 55)/(23 + 12 + 17 + 55) x 100 ] % = [ 67/107 x 100 ] % = 62.62%.
Section C [ (8 + 46)/(17 + 8 + 9 + 46) x 100 ] % = [ 54/80 x 100 ] % = 67.5%
Section D [ (13 + 76)/(27 + 13 + 15 + 76) x 100 ] % = [ 89/131 x 100 ] % = 67.94%
Clearly, the success rate in annual examination is maximum for Section A
A school has four sections A, B, C, D of Class IX students.
The results of half yearly and annual examinations are shown in the table given below.
Which section has the maximum pass percentage in at least one of the two examinations?
Section A
Section B
Section C
Section D
Correct answer is D
Pass percentages in at least one of the two examinations for different sections are:
For Section A [ (14 + 6 + 64)/(28 + 14 + 6 + 64) x 100 ] % = [ 84/112 x 100 ] % = 75%
For Section B [ (12 + 17 + 55)/(23 + 12 + 17 + 55) x 100 ] % = [ 84/107 x 100 ] % = 78.5%
For Section C [ (8 + 9 + 46)/(17 + 8 + 9 + 46) x 100 ] % = [ 63/80 x 100 ] % = 78.75%
For Section D [ (13 + 15 + 76)/(27 + 13 + 15 + 76) x 100 ] % = [ 104/131 x 100 ] % = 79.39%
Clearly, the pass percentage is maximum for Section D.
A school has four sections A, B, C, D of Class IX students.
The results of half yearly and annual examinations are shown in the table given below.
How many students are there in Class IX in the school?
336
189
335
430
Correct answer is D
Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:
= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)
= 430