Data Interpretation questions and answers

Data Interpretation Questions and Answers

Data Interpretation questions test one's ability in analysing data, inspecting the elements in data and interpreting them to extract maximum information from the given set of data or information. The data is usually given in the form of charts, tables and graphs.

Practise with our Data Interpretation questions and answers to help you know what to expect, improve your speed and confidence and be really prepared for the actual test.

201.

A soft drink company prepares drinks of three different flavours - X, Y and Z. The production of three flavours over a period of six years has been expressed in the bar graph provided below.

Production of Three Different Flavours X, Y and Z by a Company over the years (in lakh bottles)

What is the difference between the average production of flavour X in 1995, 1996 and 1997 and the average production of flavour Y in 1998, 1999 and 2000?

A.

50,000 bottles

B.

80,000 bottles

C.

240,000 bottles

D.

500,000 bottles

Correct answer is D

Average production of flavour X in 1995, 1996 and 1997

= [ 1/3 x (50 + 40 + 55) ]

= ( 145/3 ) lakh bottles. 

Average production of flavour Y in 1998, 1999 and 2000

= [ 1/3 x (55 + 50 + 55) ]

= ( 160/3 ) lakh bottles.

Therefore Difference = ( 160/3 - 145/3 )

= 15/3

= 5 lakh bottles

= 500,000 bottles.

202.

A soft drink company prepares drinks of three different flavours - X, Y and Z. The production of three flavours over a period of six years has been expressed in the bar graph provided below.

Production of Three Different Flavours X, Y and Z by a Company over the years (in lakh bottles)

For which flavour was the average annual production maximum in the given period?

A.

X only

B.

Y only

C.

Z only

D.

X and Y

Correct answer is B

Average annual productions over the given period for various flavours are:

For Flavour X = [ 1/6 x (50 + 40 + 55 + 45 + 60 + 50) ] = 50 lakh bottles.

For Flavour Y = [ 1/6 x (55 + 60 + 50 + 55 + 50 + 55) ] = 54.17 lakh bottles.

For Flavour Z = [ 1/6 x (45 + 50 + 60 + 60 + 45 + 40) ] = 50 lakh bottles.

Therefore Maximum average production is for Flavour Y.

203.

A soft drink company prepares drinks of three different flavours - X, Y and Z. The production of three flavours over a period of six years has been expressed in the bar graph provided below.

Production of Three Different Flavours X, Y and Z by a Company over the years (in lakh bottles)

The total production of flovour Z in 1997 and 1998 is what percentage of the total production of flavour X in 1995 and 1996?

A.

96.67%

B.

102.25%

C.

115.57%

D.

133.33%

Correct answer is D

Required percentage

= [ (60 + 60)/(50 + 40) x 100 ] %

= [ 120/90 x 100 ] % = 133.33%.

204.

A cosmetic company provides five different products. The sales of these five products (in lakh number of packs) during 1995 and 2000 are shown in the following bar graph.

Sales (in lakh number of packs) of five different products of Cosmetic Company during 1995 and 2000

The sales of conditioners in 1995 was by what percent less than the sales of shampoos in 1995? (rounded off to nearest integer)

A.

57%

B.

36%

C.

29%

D.

25%

Correct answer is B

Required percentage = [ (7.88 - 5.01)/7.88 x 100 ] %

= 36.42%

≈ 36%

205.

A cosmetic company provides five different products. The sales of these five products (in lakh number of packs) during 1995 and 2000 are shown in the following bar graph.

Sales (in lakh number of packs) of five different products of Cosmetic Company during 1995 and 2000

The sales have increased by nearly 55% from 1995 to 2000 in the case of?

A.

Lipsticks

B.

Nail enamels

C.

Talcum powders

D.

Shampoos

Correct answer is D

The percentage increase from 1995 to 2000 for various products are:

Lipsticks = [ (48.17 - 20.15)/20.15 x 100 ] % = 139.06%

Nail enamels = [ (37.76 - 5.93)/5.93 x 100 ] % = 536.76%

Talcum powders = [ (29.14 - 14.97)/14.97 x 100 ] % = 94.66%

Shampoos = [ (12.21 - 7.88)/7.88 x 100 ] % = 54.95% ≈ 55%

Conditioners = [ (10.19 - 5.01)/5.01 x 100 ] % = 103.39%