Chemistry questions and answers

Chemistry Questions and Answers

Learn more about the properties, composition, and structure of substances (elements and compounds) with these Chemistry questions and answers. This Test can be used by students preparing for Chemistry in JAMB, WAEC, NECO or Post UTME.

916.

Which of the following represents a precipitation reaction?

A.

H2SO4 + NaCl \(\to\) NaHSO4 + HCl

B.

Fe +H2SO4 \(\to\) FeSO4 + H2

C.

4HCl + MnO2 \(\to\) MnCl2 + 2H2O + Cl2

D.

Na2SO4 + pb(NO3) \(\to\) PbSO4 + 2NaNO

E.

CuO +2HCl \(\to\) Cl2 + H2O

Correct answer is D

No explanation has been provided for this answer.

917.

1.00g of mixture of calcium carbonate and calcium oxide liberated 0.33g of carbon dioxide on strong heating. The percentage of calcium oxide in the mixture is? (Ca = 40, C = 12, O = 16)

A.

5

B.

15

C.

25

D.

35

E.

50

Correct answer is C

CaCO3 + CaO \(\to\) 2CaO + 2CO2

44gm of CO3 is liberated by 100gm of CaCO3

0.33gm of CO2 will be liberated by \(\frac{100}{44}\) x 0.33

= 0.75 of CaCO3

Amount of CaO = 1 - 0.75

= 0.25

% of CaO = \(\frac{0.25}{1} \times \frac{100}{1}\)

= 25%

918.

In the experiment above, a current was passed for 10 minutes, and 0.63g of copper was found to be deposited on the cathode of CuSO4 cells. The weight of silver deposited on the cathode of AgNO3 cell during the same period would be? [Cu = 63, Ag = 108]

A.

0.54g

B.

1.08g

C.

1.62g

D.

2.16g

E.

3.24g

Correct answer is D

Same period, Same current

\(Cu^{2+} + 2e^- → Cu;  2Ag^+ + 2e^-\) → Ag

From the equation above, 2 mol Ag ≡ 1 mol Cu

But 0.63g Cu = \(\frac{0.63}{63}\) = 0.01mole Cu

Hence 0.002 mole Ag is deposited

mass of Ag deposited = 0.002 x 108 = 2.16g.

919.

In the above experiment, the litmus paper will initially

A.

be bleached

B.

turn green

C.

turn red

D.

turn blue

E.

turn black

Correct answer is D

No explanation has been provided for this answer.

920.

Copper sulphate solution is electolysed using platinum electrodes A. current of 0.193 amperes is passed for 2hrs. How many grams of copper are deposited? (cu = 63.5, F = 96500 coulombs)

A.

0.457g

B.

0.500g

C.

0.882g

D.

0.914g

E.

1.00g

Correct answer is A

Time = 2hrs = 120mins = 120 x 60secs =7200secs.

current = 0.193amps

Quantity of electricity = 7200 x 0.193 = 1389.6

2 x 96,500 deposits 63.5 gms of Cu

1389.6  will deposit \(\frac{63.5 \times 1389.6}{2 \times 96500}\)

= 0.457g