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Chemistry questions and answers

Chemistry Questions and Answers

Learn more about the properties, composition, and structure of substances (elements and compounds) with these Chemistry questions and answers. This Test can be used by students preparing for Chemistry in JAMB, WAEC, NECO or Post UTME.

691.

The densities of two gases, X and Y are 0.5gdm-3 and 2.0gdm-3 respectively. What is the rate of diffusion of X relative to Y?

A.

0.1

B.

0.5

C.

2.0

D.

4.0

Correct answer is C

The rate of dimension of a gas inversely proportional to the square root of its molecular mass or its density, which is Graham's Law of diffusion of gas.

R ∝ 1Mm or R ∝ 1D

Dx = 0.5gdm-3, Dy = 2gdm-3

R= KD

RD = k

R1D1 = R1D2

RxDx = RyDy

RxRy = DyDx

= 20.5

= 2.0

692.

The reddish–brown rust on iron roofing sheets consists of

A.

Fe3 + (H2O)6

B.

FeO.H2O

C.

Fe2O3.XH2O

D.

Fe3O4.2H22O

Correct answer is C

Iron [Fe] reacts with H2 in the presence of oxygen to form a rust.

4Fe + 3O2 → 2 Fe2O2

Fe2O3 + H2O → Fe2O3.H2O

693.

The IUPAC nomenclature of the structure above is

A.

3-methybut-3-ene

B.

2-methylbut-1-ene

C.

2-ethylprop-1-ene

D.

2-methylbut-2-ene

Correct answer is B

CH2CH2 - CCH3CH2
Start the numbering from the terminal carbon.

694.

Calculate the mass of copper deposited when a current of 0.5 ampere was passed through a solution of copper(II) chloride for 45 minutes in an electrolytic cell. [Cu = 64, F = 96500Cmol-1]

A.

0.300g

B.

0.250g

C.

0.2242g

D.

0.448g

Correct answer is D

M = Molar mass × Quantity of Electricity96500 × no of charge

= MmIT96500n

Copper II Chloride = CuCl2

CuCl2 → Cu2+ + 2Cl2

Mass of compound deposited = Molar mass × Quantity of Electricity96500 × no of charge

Q = IT

I = 0.5A

T = 45 × 60

T = 2700s

Q = 0.5 × 2700

= 1350c

Molarmass = 64gmol-1

no of charge = + 2

Mass = 64×135096500×2

Mass = 0.448g

695.

The diagram above. Y is

A.

fused CaO

B.

H2O

C.

NaOH

D.

Concentrated H2SO4

Correct answer is D

In the preparation of sulphur dioxide by the action of dilute acids on sulphates and bisulphites. conc H2SO4 helps to release SO2 from the mixture.
The setup represents the production of sulphur dioxide