JAMB Mathematics Past Questions & Answers - Page 39

192.

Express the product of 0.0014 and 0.011 in standard form 

A.

1.54 x 10\(^{-2}\)

B.

1.54 x 10\(^{-3}\)

C.

1.54 x 10\(^{-2}\)

D.

1.54 x 10\(^{-5}\)

Correct answer is D

No explanation has been provided for this answer.

193.

The equation of the line in the graph is 

A.

3y = 3x + 12

B.

3y = 3x + 12

C.

3y = -4x + 12

D.

3y = -4x + 9

Correct answer is C

Gradient of line = \(\frac{\text{Change in y}}{\text{Change in x}}\) = \(\frac{y_2 - Y}{x_2 - x}\) 

y\(_2\)  = 0\(_1\) 

Y\(_1\)  = 4 

x\(_2\)  = 3 and x\(_1\)  = 0

\(\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}\)

Equation of straight line y = mx + c

Where m = gradient and c = y 

intercept = 4 

y = 4x + \(\frac{4}{3}\) multiply through y 

3y = 4x + 23 

194.

A number is selected at random between 20 and 30, both numbers inclusive. Find the probability that the number is a prime. 

A.

\(\frac{2}{11}\)

B.

\(\frac{5}{11}\)

C.

\(\frac{6}{11}\)

D.

\(\frac{8}{11}\)

Correct answer is A

Possible outcomes are 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30. Prime numbers have only two factors, itself and 1. The prime numbers among the group are 23, 29. 

The probability of choosing a prime number 

= \(\frac{\text{Number of Prime}}{\text{No. of Total Possible Outcome}}\)

= \(\frac{2}{11}\)

195.

 Calculate the standard deviation of the following data: 7, 8, 9, 10, 11, 12, 13 

A.

2

B.

4

C.

12

D.

17

Correct answer is A

x x - x (x - x)\(^2\)

7

8

9

10

11

12

13

 

-3

-2

-1

0

1

2

3

 

9

4

1

1

0

4

9

--------------

28

 

S.D = \(\frac{\sqrt\sum (x - x)^2}{N} = \frac{\sum d^2}{N} = \frac{\sqrt{28}}{7}\) 

= \(\sqrt{4}\) 

= 2