200 g
160 g
100 g
50 g
Correct answer is C
Ma = (MbVb)/(Va) = (0.1 m χ 20 cm3)/(25cm) = 0.08 m
M = (concentration in g/dm3)/(m) = (8)/(0.08) = 100 g
1.40 χ 102 dm3
14.0 χ 102 cm3
1.40 χ 10-2 dm-2
14.0 χ 10-2 cm3
Correct answer is A
Na2C2O4 + CaCl2 → CaC2O4 + 2NaCl
molar mass of Na2C2O4 = 134
molarity in 1000g H2O = (1.9)/(134) = 0.014 m
but in 502 g mole = (0.014)/(50) χ 1000 = 0.28 m
M1V1 = M2V2
V2 = (M1V1)/(M2) = (0.28 χ 50)/(0.1) = 140
= 1.40 χ 102 dm3
solid particles dispersed in liquid
solid or liquid particles dispersed in gas
gas or liquid particles dispersed inliquid
liquid particles dispersed inliquid
Correct answer is B
No explanation has been provided for this answer.
0.13
0.25
1.25
2.00
Correct answer is C
Solubility in moles per dm3
No of moles = (20)/(159.5) χ 0.125 moles
in 100 g of moles = (0.125)/(100) χ 1000 = 1.25 moles
is deliquescent
is hydroscopic
has some molecules of water of crystallization
is efflorescent
Correct answer is A
No explanation has been provided for this answer.