28 dm3
56 dm3
112 dm3
196 dm3
Correct answer is C
2KHCOdm3 → K2CO3 + H2O + CO2
2(39 + 1 + 12 + 48) 22.4 dm3
200 g 22.4 dm3 of CO2
1000 g (1000) / (200) x 22.4 = 112 dm3
6.7 atm
15.0 atm
60.0 atm
66. 0 atm
Correct answer is B
P\(_1\)V\(_1\) = P\(_2\)V\(_2\) (where T is kept constant)
30 x 10 = P\(_2\) x 20
P\(_2\) = \(\frac{30 \times 10}{20}\)
= 15.0 atm
multiple proportion
conservation of mass
constant composition
reciprocal proportion
Correct answer is C
0.36g of Cl combines with 0.2g of x
1g of Cl will combine with \(\frac{1 \times 0.2}{0.32}\) = 0.56
0.71g of U combines with 0.49g of x
1g of U will combine with \(\frac{1 \times 0.4}{71}\) = 0.56
Ratio 0.56 : 0.56 = 1:1
An iron ore is known to contain 70.0% Fe2O3. The obtain from 80kg of the ore is?
(Fe = 56, O = 16)
35.0 kg
39.2 kg
70.0 kg
78.4 kg
Correct answer is B
2Fe2O3 → 4Fe + 3O2
320g 224g 96g
(70) / (100) x (80) / (1) 56g
if 0.32kg of Fe293 contains 0.224 kg
Then 56kg will contain (56 x 0.224) / (0.32) =39.2 kg
i, ii and iii
i, ii and iv
i and ii only
i and iv
Correct answer is A
No explanation has been provided for this answer.