JAMB Chemistry Past Questions & Answers - Page 310

1,546.

Calculate the volume of carbon (IV)oxide measured at s.t.p, produced when 1 kg of potassium hydrogen trioxocarbonate (IV) is totally decomposed by heat?

(G.M.V. at s.t.p 22.4 dm3, K = 39, O = 16, C = 12, H = 1)

A.

28 dm3

B.

56 dm3

C.

112 dm3

D.

196 dm3

Correct answer is C

2KHCOdm3 → K2CO3 + H2O + CO2
2(39 + 1 + 12 + 48) 22.4 dm3
200 g 22.4 dm3 of CO2
1000 g (1000) / (200) x 22.4 = 112 dm3

1,547.

30cm\(^3\) of oxygen at 10 atmospheres pressure is placed in a 20 cm\(^3\) container. Calculate the new pressure if temperature is kept constant?

A.

6.7 atm

B.

15.0 atm

C.

60.0 atm

D.

66. 0 atm

Correct answer is B

P\(_1\)V\(_1\) = P\(_2\)V\(_2\) (where T is kept constant)

30 x 10 = P\(_2\) x 20

P\(_2\) = \(\frac{30 \times 10}{20}\)

= 15.0 atm

1,548.

In two separate experiments, 0.36g and 0.71g of chlorine combined with a metal X to give Y and Z respectively. An analysis showed that Y and Z contain 0.20g and 0.40g of X respectively. The data above represents the law of ?

A.

multiple proportion

B.

conservation of mass

C.

constant composition

D.

reciprocal proportion

Correct answer is C

0.36g of Cl combines with 0.2g of x

1g of Cl will combine with \(\frac{1 \times 0.2}{0.32}\) = 0.56

0.71g of U combines with 0.49g of x

1g of U will combine with \(\frac{1 \times 0.4}{71}\) = 0.56

Ratio 0.56 : 0.56 = 1:1

1,549.

An iron ore is known to contain 70.0% Fe2O3. The obtain from 80kg of the ore is?

(Fe = 56, O = 16)

A.

35.0 kg

B.

39.2 kg

C.

70.0 kg

D.

78.4 kg

Correct answer is B

2Fe2O3 → 4Fe + 3O2
320g 224g 96g
(70) / (100) x (80) / (1) 56g
if 0.32kg of Fe293 contains 0.224 kg
Then 56kg will contain (56 x 0.224) / (0.32) =39.2 kg

1,550.

Which of the following are mixtures?
i, Petroleum
ii, Rubber latex
iii. Vulcanizer's solution
iv, Carbon (II)sulphide

A.

i, ii and iii

B.

i, ii and iv

C.

i and ii only

D.

i and iv

Correct answer is A

No explanation has been provided for this answer.