From the diagram above, if the potential difference across the resistor, capacitor and inductor are 60V, 120V and 30V respectively, the effective potential difference is
A.
81
B.
67
C.
59
D.
73
Correct answer is B
\(V_L\)=60 V ,\(V_C\) = 120 V , \(V_R\) =30V
;V = ?
; \(V^2\) = \(V_R^2\) + \(V_L\) - \(V_C^2\)
= \(V^2\) = \(30^2\) + \(60 - 120^2\)
= \(V^2\) = 900 + 3600
= \(V^2\) = 4500
= V = √4500 = 67V